x^2-36x+162=0

Solution for x^2-36x+162=0 equation:

x^2-36x+162=0

a = 1; b = -36; c = +162;
Δ = b2-4ac
Δ = -362-4·1·162
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-18\sqrt{2}}{2*1}=\frac{36-18\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+18\sqrt{2}}{2*1}=\frac{36+18\sqrt{2}}{2}
$